Convergent Sequences

A sequence an is said to be convergent if its limit as n→∞ is a finite number l: $$ \lim_{n \rightarrow \infty} a_n = l $$ In other words, for any ε > 0, there exists some number v such that: $$ l - \epsilon < a_n < l + \epsilon \quad \forall n > v $$ the limit of the sequence
Equivalently, this condition can be expressed as: $$ | a_n - l | < \epsilon \quad \forall n > v $$

Every convergent sequence is also a bounded sequence.

However, the converse is not necessarily true: a bounded sequence is not always convergent.

For instance, the sequence (-1)n oscillates between -1 and +1. It is bounded but does not converge.

Note. If a sequence converges to zero, it’s referred to as an infinitesimal sequence. This is a special case of a convergent sequence. $$ \lim_{ n \rightarrow \infty } a_n = 0 $$

    A Practical Example

    Consider the sequence:

    $$ a_n = \frac{n-1}{n} $$

    The limit of this sequence as n→∞ is one:

    $$ \lim_{ n \rightarrow \infty } \frac{n-1}{n} = 1 $$

    Therefore, the sequence is convergent because its limit as n→∞ is finite.

    an example of a convergent sequence

    Verification

    A sequence is convergent if, for every ε > 0, the following inequality holds:

    $$ | a_n - l | < \epsilon $$

    In this example, l = 1:

    $$ | a_n - 1 | < \epsilon $$

    The general term an is defined as (n-1)/n:

    $$ \left| \frac{n-1}{n} - 1 \right| < \epsilon $$

    Let’s simplify this expression through a few algebraic steps:

    $$ \left| \frac{n-1 - n}{n} \right| < \epsilon $$

    $$ \left| \frac{-1}{n} \right| < \epsilon $$

    Since n > 0, we can drop the absolute value signs:

    $$ \frac{1}{n} < \epsilon $$

    Rearranging gives us:

    $$ n > \frac{1}{\epsilon} $$

    This shows that if the index n exceeds 1/ε, the difference |an - l| will indeed be less than ε.

    Therefore, the threshold value v is equal to 1/ε:

    $$ v = \frac{1}{\epsilon} $$

    For all n > v, the condition |an - l| < ε is satisfied.

    This confirms that the sequence is convergent.

    a practical example

    Note. In the graph above, ε = 0.5, so v = 1/ε equals v = 1/0.5 = 2. For every index n > v, i.e., n > 2, the sequence an lies entirely within the neighborhood (l - ε, l + ε).

    And so on.

     

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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    Sequences in Mathematics