How to Find the Midpoint of a Line Segment

To locate the midpoint of a line segment AB, place the compass on endpoint A and open it to a width greater than half the segment's length. Draw an arc.

first arc with center A

Next, position the compass on the other endpoint B and draw a second arc using the same compass width.

second arc with center B

The two arcs will intersect at points C and D.

points C and D

The line segment connecting points C and D intersects segment AB at its midpoint, labeled M.

the midpoint of the segment

In this manner, you have found the midpoint of the segment.

Proof. By construction, the segments $ AC \cong BC \cong AD \cong BD $ are congruent. This immediately implies that triangles $ ACD $ and $ BCD $ are congruent by the third triangle congruence theorem, since they have three pairs of corresponding congruent sides.
proof
As a consequence, corresponding angles in $ \triangle ACD $ and $ \triangle BCD $ are also congruent. In particular, the key takeaway here is that $ \angle ACD \cong \angle BCD $, which tells us that segment $ CM $ is the angle bisector of $ \angle ACB $ in $ \triangle ABC $. Since $ \triangle ABC $ is an isosceles triangle (with $ AC \cong BC $), this fact is crucial.
example
In any isosceles triangle, the angle bisector from the vertex also serves as the median. Since the median necessarily intersects the midpoint of the base $ AB $, this proves that $ M $ is the midpoint of segment $ AB $.

And that's all there is to it.

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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