Odd Functions

What Are Odd Functions?

A function is called odd if for any x in its domain, the following holds: $$ f(-x) = -f(x) \ \ \ \forall \ x \ \in D $$

The graph of an odd function is symmetric about the origin, meaning that for every point P(x, y), there’s an opposite point P(-x, -y).

An example of an odd function

How Can You Tell If a Function Is Odd?

There are two ways to check:

  • From an analytical perspective, compare the value of f(-x) with -f(x). If they match, the function is odd. $$ f(-x) = -f(x) $$

    Example. Let’s take the function f(x) = x3. Replace x with -x and check if it equals -f(x). $$ f(-x) = (-x)^3 = -x^3 = -f(x) $$ Since f(-x) matches -f(x), the function is odd.

  • From a graphical point of view, reflect the graph vertically across the negative x-axis. If the graphs of g(x) and f(x) are symmetric about the origin, then the function is odd.
    How to tell if a function is odd

Note. A function doesn’t have to be odd just because it’s not even, and vice versa. For instance, the function f(x) = x + x2 is neither odd $$ f(-x) = (-x) + (-x)^2 = -x + x^2 \ne -f(x) = -x - x^2 $$ nor even. $$ f(-x) = (-x) + (-x)^2 = -x + x^2 \ne f(x) = x + x^2 $$

    A Practical Example

    A well-known example of an odd function is the sine function.

    The sine function is an odd function

    For any x in the domain of the sine function, the relation f(-x) = -f(x) holds.

    Note. For example, at x = 1, sin(1) = 0.84. When we evaluate the function at -1, we get sin(-1) = -0.84, the same as -sin(1). So, f(-x) = -f(x).

    Example 2

    Another example of an odd function is x3.

    Another example of an odd function

    For any x in the function’s domain, the relation f(-x) = -f(x) holds.

    Note. In general, if a function only contains powers of x with odd exponents, it is an odd function.

    Example 3

    Let’s analytically verify if this function is odd:

    $$ f(x) = x^2 + x $$

    Substitute x with -x in the function expression:

    $$ f(-x) = (-x)^2 + (-x) = x^2 - x $$

    The result is not the same as -f(x):

    $$ -f(x) = -(x^2 + x) = -x^2 - x $$

    So, this function is not odd.

    The function is not odd

    Note. The function f(x) = x2 + x is also not even because it’s not symmetric about the y-axis.

    And so on.

     

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

    FacebookTwitterLinkedinLinkedin
    knowledge base

    Functions

    Mathematical Analysis