Connectedness of Subspaces
A subset \( A \) of a topological space \( X \) is said to be connected in \( X \) when, equipped with the subspace topology inherited from \( X \), the set \( A \) forms a connected topological space.
This perspective extends the notion of connectedness to any subset of a topological space, not only to the space as a whole.
In practice, the question is whether a particular subset remains connected once it is viewed with the topology induced by \( X \).
Note. Concretely, we take the set \( A \), endow it with the subspace topology inherited from \( X \), and ask whether \( A \) can be written as the union of two nonempty, disjoint sets that are open in this topology. If such a decomposition exists then \( A \) is disconnected in \( X \). If no such decomposition exists then \( A \) is connected in \( X \).
A practical example
Consider the real line \( \mathbb{R} \) with its standard topology, and the subset \( A \).
$$ A = [-1,0) \cup (0,1] $$
This set omits exactly one point, namely \( 0 \).
It contains all real numbers from -1 up to 0, excluding 0, and all real numbers from 0 to 1, again excluding 0.
The absence of that single point separates \( A \) into two distinct parts:
- the interval from -1 to 0 (excluded)
- the interval from 0 (excluded) to 1
These parts are:
$$ U = [-1,0) $$
$$ V = (0,1] $$
Both \( U \) and \( V \) are open in \( A \) when considered with the subspace topology.
They are disjoint, they do not intersect, and together they exhaust the entire set \( A \). This is precisely the standard characterization of disconnectedness.
$$ U \cap V = \emptyset $$
$$ U \cup V = A $$
Hence the subspace \( A \) is disconnected in \( \mathbb{R} \).
