Whole Numerical Equations

Whole numerical equations are equations where the variable has a numerical coefficient and never appears in the denominator.

In plain language, an equation is both numerical and whole if it meets two simple conditions:

  • An equation is "whole" when the variable doesn’t appear in the denominator.

    Note. The word “whole” refers to the variable, not to the coefficients - they can still be fractions.

  • An equation is "numerical" when the coefficient of the variable is a number, not a letter or symbol.

Understanding with an example

Let’s start with a simple equation:

$$ \frac{1}{2} x + 3 = \frac{15}{2} $$

This equation is whole because x doesn’t appear in the denominator.

It’s also numerical because the coefficient of x is a number (½).

So, it’s a whole numerical equation.

Example 2

Now look at this one:

$$ \frac{1}{2x} + 3 = \frac{15}{2} $$

Here, the variable x is in the denominator - so it’s not whole.

Therefore, it’s not a whole numerical equation.

Example 3

Consider this equation:

$$ \frac{a}{2} x + 3 = \frac{15}{2} $$

It’s whole because x isn’t in the denominator, but it’s not numerical because the coefficient of x includes a literal (a).

So again, this isn’t a whole numerical equation.

First-degree whole numerical equations

A first-degree whole numerical equation with one variable has x raised to the power of 1. For example: $$ 2x = 8 $$

These equations are always reducible to the standard form ax = b:

$$ ax = b $$

Here, “a” is the coefficient of x and “b” is the constant term. Equations like these are the simplest to solve.

How to solve them

If the coefficient “a” is not zero (a≠0), the equation is called determinate because it has exactly one solution:

$$ x = \frac{b}{a} $$

Note. To find x, we use the second principle of equivalence: divide both sides by “a.” $$ ax = b $$ $$ \frac{ax}{a} = \frac{b}{a} $$ Simplify: $$ \require{cancel} \frac{\cancel{a}x}{\cancel{a}} = \frac{b}{a} $$ $$ x = \frac{b}{a} $$

Special cases

If “a” is zero (a=0), two different situations may occur:

  • Indeterminate equation: infinite solutions, when b is also zero (b=0).
  • Example. $$ 0x = 0 $$ Whatever value you assign to x (2, 3, or 100), both sides are still 0=0. So, the equation is true for every x.

  • Impossible equation: no solution, when b is not zero (b≠0).
  • Example. $$ 0x = 2 $$ No matter what x is, the left side is always 0, and the equation becomes 0=2 - which is false. So, it has no solution.

Worked example

Let’s solve this first-degree whole numerical equation:

$$ 5x - 1 = 2x + 5 $$

We apply the first principle of equivalence: subtract 2x from both sides.

$$ 5x - 1 - 2x = 2x + 5 - 2x $$

$$ 3x - 1 = 5 $$

Then add 1 to both sides:

$$ 3x - 1 + 1 = 5 + 1 $$

$$ 3x = 6 $$

Now the equation is in the form ax = b.

Since both the coefficient and the constant are nonzero, the equation is determinate - it has one solution.

Apply the second principle of equivalence again and divide both sides by 3:

$$ \frac{3x}{3} = \frac{6}{3} $$

$$ \frac{\cancel{3}x}{\cancel{3}} = 2 $$

$$ x = 2 $$

So, the solution is x = 2.

Check your result. Substitute x=2 into the original equation: $$ 5x - 1 = 2x + 5 $$ $$ 5 \cdot 2 - 1 = 2 \cdot 2 + 5 $$ Simplify: $$ 10 - 1 = 4 + 5 $$ $$ 9 = 9 $$ The equation holds true - x=2 is correct.

And that’s how you solve whole numerical equations step by step.

 

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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