Basic Operations on Series

The fundamental operations on regular series are addition and multiplication by a constant, also known as scalar multiplication.

Sum of Two Series

Let the series with general terms ak and bk be regular series. If the expression $$ \sum_{k=1}^{\infty} a_k + \sum_{k=1}^{\infty} b_k $$ is well-defined in the extended real numbers \( \mathbb{R} \cup \{\pm \infty\} \), then the series with general term ak+bk is also a regular series, and $$ \sum_{k=1}^{\infty} (a_k+b_k) = \sum_{k=1}^{\infty} a_k + \sum_{k=1}^{\infty} b_k $$

A worked example

Consider the following two series

$$ a_n = \sum_{k=1}^{n} \frac{2}{2^k} $$

$$ b_n = \sum_{k=1}^{n} \frac{3}{3^k} $$

Both are regular series, since they are convergent

$$ \lim_{ n \rightarrow \infty } \sum_{k=1}^{n} \frac{2}{2^k} = 2 $$

$$ \lim_{ n \rightarrow \infty } \sum_{k=1}^{n} \frac{3}{3^k} = 3 $$

Note. A series is called regular if it is either convergent or divergent, that is, if the limit of the sequence of partial sums exists in the extended real numbers, either as a finite real number or as \( \pm \infty \).

The following figure shows the graphical representation of the two series in the Cartesian plane

graphical representation of the two series in the Cartesian plane

Their sum is well-defined in the extended real numbers

Note. The sum must be well-defined in the extended real numbers. For instance, the sum of two finite numbers (l1+l2) is always defined. The sum of a finite number and infinity is also defined (l1+∞). By contrast, the expression (∞-∞) is indeterminate and therefore not defined.

It follows that the series obtained by adding the two series term by term is also a regular series

$$ (a_n + b_n) = \sum_{k=1}^{n} \left( \frac{2}{2^k} + \frac{3}{3^k} \right) $$

$$ (a_n + b_n) = \sum_{k=1}^{n} \left( \frac{2}{2^k} + \frac{3}{3^k} \right) $$

Moreover, this series is convergent and its sum is equal to 5

$$ \lim_{ n \rightarrow \infty } (a_n + b_n) $$

$$ \lim_{ n \rightarrow \infty } \sum_{k=1}^{n} \left( \frac{2}{2^k} + \frac{3}{3^k} \right) = 5 $$

From a graphical perspective

the sum of the two series is a regular and convergent series

Scalar Multiplication of a Series

Let c be a real constant. If the series with general term ak is a regular series, then the series with general term c·ak is also a regular series, and $$ \sum_{k=1}^{\infty} c \cdot a_k = c \cdot \sum_{k=1}^{\infty} a_k $$

A worked example

Consider the series

$$ s_n = \sum_{k=1}^{n} \frac{1}{2^k} $$

This is a convergent series, since as n→∞ it converges to 1

$$ \lim_{ n \rightarrow \infty } \sum_{k=1}^{n} \frac{1}{2^k} = 1 $$

The graph of the series is shown below

graph of the convergent series in the Cartesian plane

 

Now multiply the series by c = 2

$$ s_n = \sum_{k=1}^{n} 2 \cdot \frac{1}{2^k} $$

Since the series is regular, because it is convergent, we can apply the rule of scalar multiplication

$$ s_n = 2 \cdot \sum_{k=1}^{n} \frac{1}{2^k} $$

The series 2·sn is also regular and convergent

$$ \lim_{ n \rightarrow \infty } 2 \cdot \sum_{k=1}^{n} \frac{1}{2^k} = 2 $$

Thus, the series 2·sn converges to 2

the series is regular and converges to 2

And so on.

 

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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