One-to-One Mapping Between Vectors and Points in the Plane

Every point \( P \) in the plane, defined by its coordinates \( (x, y) \), can be uniquely associated with a vector \( \vec{v} = \begin{pmatrix} x \\ y \end{pmatrix} \). This vector, known as the position vector, originates from the origin \( O \) and terminates at \( P \). The reverse association also holds true.
example

In other words, there is a perfect one-to-one relationship between points in the plane \( P \) and vectors in the vector space \( \mathbb{R}^2 \). 

This means that points in the plane and vectors in \( \mathbb{R}^2 \) can be seen as "two perspectives on the same concept": a point can be represented by a vector, and a vector specifies a unique point.

This correspondence depends on choosing an origin \( O \), which serves as the reference point for defining position vectors.

The mapping between points in the plane and vectors in \( \mathbb{R}^2 \) is one-to-one because:

  • Each point in the plane corresponds to a unique position vector
    Every point \( P(x, y) \) is represented by exactly one vector \( \vec{OP} = \begin{pmatrix} x \\ y \end{pmatrix} \).
  • Each vector corresponds to a unique point
    Any vector \( \begin{pmatrix} x \\ y \end{pmatrix} \) corresponds to a single point \( P(x, y) \) in the plane.

    Example 

    For example, if a point in the plane has coordinates \( P(3, 2) \), its corresponding vector is:

    $$ \vec{OP} = \begin{pmatrix} 3 \\ 2 \end{pmatrix} $$

    Conversely, given a vector \( \vec{v} = \begin{pmatrix} 3 \\ 2 \end{pmatrix} \), it can be associated with the point \( P(3, 2) \) in the plane.

    a practical example

    And so on.

     

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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