Vector Representation of a Line

A geometric vector identifies a direction shared by all lines in the plane parallel to the vector.

example of a geometric vector and lines parallel to the vector

Therefore, any line in the plane can be described by:

  • a non-trivial geometric vector vr, known as the direction vector, which indicates the line's direction $$ v_r = \begin{pmatrix} l \\ m \end{pmatrix} $$

    The parameters l and m are the line's directional parameters.

  • a generic point P0 on the plane through which the line passes. $$ P_0 = \begin{pmatrix} x_0 \\ y_0 \end{pmatrix} $$

    Example
    a practical example

A generic point on the plane belongs to the line if there exists a scalar alpha in R such that

$$ OP = OP_0 + \alpha v_r $$

Example

The point P1 has coordinates (-5,-3).

point P1 is on the line

Point P1 belongs to the line if

$$ OP_1 = OP_0 + \alpha v_r $$

$$ \begin{pmatrix} -5 \\ -3 \end{pmatrix} = \begin{pmatrix} 2 \\ 4 \end{pmatrix} + \alpha \begin{pmatrix} 5 \\ 5 \end{pmatrix} $$

Solving the system of equations to check for a scalar alpha

$$ \begin{cases} -5 = 2 + \alpha 5 \\ -3 = 4 + \alpha 5 \end{cases} = \begin{cases} \alpha = - \frac{7}{5} \\ \alpha = - \frac{7}{5} \end{cases} $$

The system resolves with the scalar alpha -7/5

Indeed

$$ \begin{pmatrix} -5 \\ -3 \end{pmatrix} = \begin{pmatrix} 2 \\ 4 \end{pmatrix} + \alpha \begin{pmatrix} 5 \\ 5 \end{pmatrix} $$

$$ \begin{pmatrix} -5 \\ -3 \end{pmatrix} = \begin{pmatrix} 2 \\ 4 \end{pmatrix} + \begin{pmatrix} 5 \cdot ( - \frac{7}{5} ) \\ 5 \cdot ( - \frac{7}{5} ) \end{pmatrix} $$

$$ \begin{pmatrix} -5 \\ -3 \end{pmatrix} = \begin{pmatrix} 2 - 7 \\ 4 - 7 \end{pmatrix} $$

$$ \begin{pmatrix} -5 \\ -3 \end{pmatrix} = \begin{pmatrix} -5 \\ -3 \end{pmatrix} $$

We can generalize this result by stating that

All coordinates of all points on the line are characterized by the following equation, called the vector equation of the line: $$ \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} x_0 \\ y_0 \end{pmatrix} + \alpha \cdot \begin{pmatrix} l \\ m \end{pmatrix} $$Transforming the vector equation into a system of equations, we get the parametric equations of the line:$$ \begin{cases} x = x_0 + \alpha l \\ y = y_0 + \alpha m \end{cases} $$

There are infinite vector and parametric equations because there are infinite multiples of the direction vector.

Cartesian Equations

The vector P0P1 is parallel to the direction vector vr.

According to theory, a vector is parallel and proportional to another if

$$ \begin{pmatrix} x-x_0 & l \\ y - y_0 & m \end{pmatrix} \le 1 $$

This is verified if

$$ det \begin{pmatrix} x-x_0 & l \\ y - y_0 & m \end{pmatrix} = 0 $$

which, upon calculating the determinant, becomes

$$ m ( x-x_0 ) - l ( y - y_0 ) = 0 $$

This results in the Cartesian equation.

Again, there are infinite Cartesian equations.

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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