Opposite Complex Numbers

Two complex numbers, \( z \) and \( -z \), are called opposite complex numbers if their real and imaginary parts have opposite signs: $$ z = a + bi $$ $$ -z = -a - bi $$

To find the opposite of a complex number \( z \), simply reverse the signs of both its real and imaginary components.

A Practical Example

Let's take a complex number \( z \):

$$ z = 2 + 3i $$

Its opposite has the same magnitude for both the real and imaginary parts, but with reversed signs:

$$ -z = -2 - 3i $$

While the absolute values remain unchanged, the signs are flipped.

Example 2

Now, consider the complex number:

$$ z = 2 - 3i $$

Its opposite is:

$$ -z = -2 + 3i $$

Note. The opposite of a complex number can be found by multiplying it by -1: $$ z \cdot (-1) = (2 - 3i) \cdot (-1) = 2 \cdot (-1) - 3i \cdot (-1) = -2 + 3i $$

Opposite vs. Conjugate Complex Numbers

Two complex numbers are:

  • Opposite complex numbers if both their real and imaginary parts have opposite signs: $$ z = a + bi $$ $$ -z = -a - bi $$
  • Conjugate complex numbers if they share the same real part but have opposite imaginary parts: $$ z = a + bi $$ $$ z' = a - bi $$

    Note. In the case of conjugates, the real part (\( a \)) remains unchanged, while the imaginary part (\( b \)) switches sign to \( -b \).

Example

Let's take the complex number \( z = 2 + 3i \):

$$ z = 2 + 3i $$

Its opposite is:

$$ -z = -2 - 3i $$

The complex conjugate is:

$$ z' = 2 - 3i $$

Properties of Opposite Complex Numbers

Here are some key properties of opposite complex numbers:

  • The sum of a complex number and its opposite is always zero: $$ z + (-z) = 0 $$

    Proof. Consider two opposite complex numbers, \( z = a + bi \) and \( -z = -a - bi \). Adding them together results in zero since their real and imaginary parts cancel each other out: $$ z + (-z) = (a + bi) + (-a - bi) = a + bi - a - bi = 0 $$

And so on.

 

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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Complex Numbers