Relationship Between the Slopes of Two Perpendicular Lines

When two lines are perpendicular, the slope of one line is the negative reciprocal of the slope of the other: $$ m_1 = - \frac{1}{m_2} $$

Here, m1 represents the slope of one line:

$$ r_1: \ \ y = m_1 \cdot x + q $$

while m2 represents the slope of the other line:

$$ r_2: \ \ y = m_2 \cdot x + q $$

A Practical Example

Let’s take two lines:

$$ r_1 : \ \ y = -4x + 2 $$

$$ r_2 : \ \ y = \frac{1}{4} \cdot x + 4 $$

Notice that the slopes of these lines are indeed negative reciprocals:

$$ m_1 = -4 $$ $$ m_2 = \frac{1}{4} $$

This confirms the perpendicularity condition:

$$ m_1 = - \frac{1}{m_2} $$

Thus, the two lines are perpendicular.

To verify this, I’ll graph them in GeoGebra and measure the angle at their intersection.

the lines are perpendicular

 

The intersection angle between these two lines is indeed a right angle of 90°.

The Proof

Consider two perpendicular lines, r1 and r2, intersecting at point P to form a 90° angle (π/2).

two perpendicular lines

Line r1 intersects the x-axis at point A, creating angle α1, while line r2 intersects it at point B, creating angle α2.

Connecting points A, B, and P forms a right triangle, ABP.

In this triangle, we know the intersection angle is 90° (π/2), along with angle α1.

supplementary angle

Angle α2 is an exterior angle and a supplementary angle to the interior angle α2'.

Since the sum of a triangle’s angles is always 180°, the supplementary angle α2 equals the sum of the non-adjacent interior angles:

$$ a_2 = \frac{\pi}{2} + a_1 $$

Applying the tangent function (tan) to both sides, we get:

$$ \tan a_2 = \tan ( \frac{\pi}{2} + a_1 ) $$

Since the associated angle for tangent, tan(180°+x), equals -cot(x):

$$ \tan a_2 = -\cot(a_1) $$

Knowing that cotangent (cot) is the reciprocal of tangent:

$$ \tan a_2 = - \frac{1}{\tan(a_1)} $$

The tangent of angle α2 gives the slope m2 of one line, so tan α2 = m2:

$$ m_2 = - \frac{1}{\tan(a_1)} $$

The tangent of angle α1 gives the slope m1 of the other line, so tan α1 = m1:

$$ m_2 = - \frac{1}{m_2} $$

This completes the proof of the formula we set out to demonstrate.

And so on.

 

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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