Associated Angles in Trigonometry

Associated angles are angles expressed in radians that have the same trigonometric function values in absolute terms. They are also known as associated arcs.

A practical example

The sine of angle α is equal to the absolute value of the sine of -α.

$$ \sin(\alpha) = |\sin(-\alpha)| $$

Therefore, angles α and -α are associated angles for the sine function because they yield the same absolute value.

sine of minus alpha equals minus sine of alpha

Knowing that the sine function is odd, f(-x) = -f(x), we can calculate the sine of -α using the associated angle α.

$$ \sin(-\alpha) = -\sin(\alpha) $$

Note: Angles α and -α are also associated angles for the cosine function. $$ \cos(\alpha) = |\cos(-\alpha)| $$ Both functions return the same absolute value for cosine.
cosine of minus alpha equals cosine of alpha
Since cosine is an even function, f(-x) = f(x), the cosine of -α can also be found using the associated angle: $$ \cos(\alpha) = \cos(-\alpha) $$

What are they used for?

In trigonometry, associated angles allow us to reduce trigonometric functions with arguments in other quadrants (π/2; 2π) to the first quadrant (0; π/2).

Reducing to the first quadrant simplifies calculations.

Example: To calculate the cosine of -20°, $$ \cos(-20°) $$, which is in the IV quadrant. Knowing that cosine has the same value for opposite angles, we can reduce the formula to the first quadrant: $$ \cos(-20°) = \cos(20°) $$

    Formulas for Associated Angles

    Here are the main formulas for associated angles in trigonometry:

    Associated Angles Formulas Proof
    $$ \alpha \ \ , \ \ -\alpha $$ $$ \sin(-\alpha) = -\sin(\alpha) $$ $$ \cos(-\alpha) = \cos(\alpha) $$ $$ \tan(-\alpha) = -\tan(\alpha) $$ $$ \cot(-\alpha) = -\cot(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ \pi + \alpha $$ $$ \sin(\pi+\alpha) = -\sin(\alpha) $$ $$ \cos(\pi+\alpha) = -\cos(\alpha) $$ $$ \tan(\pi+\alpha) = \tan(\alpha) $$ $$ \cot(\pi+\alpha) = \cot(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ \pi - \alpha $$ $$ \sin(\pi-\alpha) = \sin(\alpha) $$ $$ \cos(\pi-\alpha) = -\cos(\alpha) $$ $$ -\tan(\pi-\alpha) = \tan(\alpha) $$ $$ -\cot(\pi-\alpha) = \cot(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ 2\pi - \alpha $$ $$ \sin(2\pi-\alpha) = -\sin(\alpha) $$ $$ \cos(2\pi-\alpha) = \cos(\alpha) $$ $$ -\tan(2\pi-\alpha) = \tan(\alpha) $$ $$ -\cot(2\pi-\alpha) = \cot(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ \frac{\pi}{2} + \alpha $$ $$ \sin(\frac{\pi}{2} + \alpha) = \cos(\alpha) $$ $$ \cos(\frac{\pi}{2} + \alpha) = -\sin(\alpha) $$ $$ \tan(\frac{\pi}{2} + \alpha) = -\cot(\alpha) $$ $$ \cot(\frac{\pi}{2} + \alpha) = -\tan(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ \frac{\pi}{2} - \alpha $$ $$ \sin(\frac{\pi}{2} - \alpha) = \cos(\alpha) $$ $$ \cos(\frac{\pi}{2} - \alpha) = \sin(\alpha) $$ $$ \tan(\frac{\pi}{2} - \alpha) = \cot(\alpha) $$ $$ \cot(\frac{\pi}{2} - \alpha) = \tan(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ \frac{3\pi}{2} + \alpha $$ $$ \sin(\frac{3\pi}{2} + \alpha) = -\cos(\alpha) $$ $$ \cos(\frac{3\pi}{2} + \alpha) = \sin(\alpha) $$ $$ \tan(\frac{3\pi}{2} + \alpha) = -\cot(\alpha) $$ $$ \cot(\frac{3\pi}{2} + \alpha) = -\tan(\alpha) $$ see explanation
    $$ \alpha \ \ , \ \ \frac{3\pi}{2} - \alpha $$ $$ \sin(\frac{3\pi}{2} - \alpha) = -\cos(\alpha) $$ $$ \cos(\frac{3\pi}{2} - \alpha) = -\sin(\alpha) $$ $$ \tan(\frac{3\pi}{2} - \alpha) = \cot(\alpha) $$ $$ \cot(\frac{3\pi}{2} - \alpha) = \tan(\alpha) $$ see explanation

    And so on.

     

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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