Associated Angles α and 2π-α in Trigonometry

In trigonometry, the angles alpha (α) and 2π-α are associated, allowing us to apply the following transformation formulas: $$ \sin(2 \pi - \alpha) = - \sin(\alpha) $$ $$ \cos(2 \pi - \alpha) = \cos(\alpha) $$ $$ \tan(2 \pi - \alpha) = - \tan(\alpha) $$ $$ \cot(2 \pi - \alpha) = - \cot(\alpha) $$

Because associated angles α and 2π-α are linked, their trigonometric functions—sine, cosine, tangent, and cotangent—share the same absolute values.

Proof and Explanation

Let’s take the angle α and the angle 2π-α on the unit circle.

The angles α and π-α are supplementary angles because their sum equals 360° (2π), which is a full circle.

example of supplementary angles

The sine (y') and cosine (x') values for the angle π-α (blue) are the same as those for the oriented angle -α (green).

a practical example

This case can be proven using the same proof for opposite angles α and -α, which I recommend for further study.

example of opposite angles

The transformation formulas for associated angles α and π-α, and those for α and -α, are identical.

A Practical Example

Let’s calculate the sine of 330°

$$ \sin 330° $$

We can rewrite this angle as 360° - 30°

$$ \sin 330° = \sin (360° - 30°) $$

In radians, this becomes

$$ \sin 330° = \sin \left( 2 \pi - \frac{\pi}{6} \right) $$

The angles 2π-α and α are associated, with α=π/6 (which corresponds to 30°).

$$ \sin( 2 \pi - \alpha ) = - \sin(\alpha) $$

Therefore, the sine of 330° is the negative of the sine of 30°

$$ \sin 330° = \sin \left( 2 \pi - \frac{\pi}{6} \right) = - \sin \left( \frac{\pi}{6} \right) $$

Since we know the sine of 30° is 1/2, the sine of 330° is -1/2.

$$ \sin 330° = \sin \left( 2 \pi - \frac{\pi}{6} \right) = - \sin \left( \frac{\pi}{6} \right) = - \frac{1}{2} $$

$$ \sin 330° = - \frac{1}{2} $$

And that's how it works.

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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