Boundary of Set A={c} in X={a,b,c} with Topology {X, Ø , {a}, {a,b}}

To determine the boundary (∂A) of the set \( A = \{c\} \) in \( X = \{a, b, c\} \) with the topology \(\{X, \{a\}, \{a, b\}, \emptyset\}\), we need to find the closure (\(\text{Cl}(A)\)) and the interior (\(\text{Int}(A)\)) of \(A\), and then calculate the boundary as the difference between the closure and the interior.

In the given topology, the closed sets are the complements of the open sets: \(\{X, \{a\}, \{a, b\}, \emptyset\}\).

The closed sets are thus: \(\{X, \{c\}, \{b, c\}, \emptyset\}\). 

The set \( A = \{c\} \) is a singleton. The closure of \(A\) is the smallest closed set that contains \(A\).

In this case, the smallest closed set containing \(\{c\}\) is \(\{c\}\) itself.

$$ \text{Cl}(A) = \{c\} $$

The interior of \(A\) is the union of all open sets contained in \(A\).

In the given topology, the open sets are \(\{X, \emptyset, \{a\}, \{a, b\}\}\).

There is no open set contained within \(\{c\}\), as none of the given open sets include \(c\). Therefore, the interior of \(A\) is the empty set.

$$ \text{Int}(A) = \emptyset $$

Now, we calculate the boundary of \(A\) as the difference between its closure and its interior:

$$ \partial A = \text{Cl}(A) - \text{Int}(A) $$

$$ \partial A = \{c\} - \emptyset $$

$$ \partial A = \{c\} $$

Therefore, the boundary of \(A = \{c\}\) in \(X = \{a, b, c\}\) with the topology \(\{X, \{a\}, \{a, b\}, \emptyset\}\) is $ \partial A = \{c\} $.

    Alternative Method

    Using the definition of the boundary as the intersection of the closure of \(A\) and the closure of the complement of \(A\):

    $$ \partial A = \text{Cl}(A) \cap \text{Cl}(X - A) $$

    The smallest closed set containing \(\{c\}\) is \(\{c\}\).

    $$ \text{Cl}(A) = \{c\} $$

    The complement of \(A\) is \( X - A = \{a, b\} \)

    The closure of the complement of \(A\) is the smallest closed set containing \(\{a, b\}\).

    In this topology, the closed sets are \(\{X, \{c\}, \{b, c\}, \emptyset\}\).

    The smallest closed set containing \(\{a, b\}\) is \(X\) itself, that is, \(\{a, b, c\}\).

    $$ \text{Cl}(X - A) = \{a, b, c\} $$

    Now, we calculate the intersection of the closures:

    $$ \partial A = \text{Cl}(A) \cap \text{Cl}(X - A) $$

    $$ \partial A = \{c\} \cap \{a, b, c\} $$

    The intersection of these sets is \(\{c\}\).

    $$ \partial A = \{c\} $$

    Therefore, the boundary of \(A = \{c\}\) in \(X = \{a, b, c\}\) with the topology \(\{X, \{a\}, \{a, b\}, \emptyset\}\) is $ \partial A = \{c\} $.

    And so on.

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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