Semicircumference

A semicircumference represents half of an entire circumference.
a semicircumference AB

When you draw a diameter across a circle, it divides the circumference into two equal arcs, each one forming a semicircumference.

The length of a semicircumference is exactly half the total circumference of the circle.

$$ S_c = \pi \cdot r $$

Explanation. If r is the radius of the circle and the circumference is given by C = 2πr, then the length of a semicircumference is simply πr. $$ S_c = \frac{C}{2} = \frac{2 \pi \cdot r}{2} = \pi \cdot r $$

The region enclosed between the diameter and the semicircumference is called a semicircle.

The area of a semicircle is precisely half the area of the full circle.

$$ A_{sc} = \frac{r^2 \pi}{2} $$

Explanation. Since the area of a circle is A = πr2, the area of a semicircle is calculated as follows: $$ A_{sc} = \frac{A}{2} = \frac{r^2 \pi}{2} $$

    Remarks

    Here are some key facts and observations about semicircumferences:

    • Any angle inscribed in a semicircumference is a right angle
      This property is widely used in Euclidean geometry.

      Proof. Consider a circle with center O and a diameter AB.
      a semicircumference AB
      Pick any point C on the semicircumference between points A and B. We want to prove that angle ACB is a right angle (90°).
      point C on the semicircumference
      Draw segment OC.
      segment OC
      Since OA and OB are both radii of the circle, they’re equal in length: OA ≅ OB. Likewise, OC is also a radius and is therefore equal in length to OA and OB. $$ \overline{OA} = \overline{OB} = \overline{OC} $$ The central angle AOC subtends arc AC, while angle BOC subtends arc BC. The central angle AOB, which spans the entire arc ACB, measures 180° because it extends across a semicircumference.
      angles in the circle
      The inscribed angle theorem states that an angle inscribed in a circle is equal to half the measure of the central angle that subtends the same arc. Therefore, if the central angle spanning arc ACB measures 180°, then the inscribed angle ACB is half of that, i.e. 90°. Hence, angle ACB is a right angle.
      inscribed right angle

    • Any triangle inscribed in a semicircumference is a right triangle, with the diameter serving as its hypotenuse
      This result also follows directly from the inscribed angle theorem. Since the central angle is 180°, the corresponding inscribed angle measures half of that, i.e. 90°.

      example of a right triangle inscribed in a semicircumference

    And so on.

     

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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