Indeterminate Forms in Limits

When working with limits, you may come across an indeterminate form - a situation where the result isn’t immediately clear and further analysis is required. These are the most common indeterminate forms in limit problems:
main indeterminate forms in limits: infinity minus infinity, zero times infinity, infinity over infinity, zero over zero, infinity to the power of zero, zero to the power of zero, one to the power of infinity

Just because a limit results in an indeterminate form doesn’t mean the limit doesn’t exist.

To evaluate it, the expression must be rewritten or simplified in a way that removes the source of indeterminacy.

How to Resolve an Indeterminate Form

There are several strategies you can use to evaluate limits that take on an indeterminate form:

  • Algebraic manipulation. Sometimes, a limit becomes solvable after applying a few algebraic transformations. Rewriting the expression in an equivalent form can often eliminate the ambiguity. However, this approach isn’t always straightforward, and a suitable transformation may not always exist.

    Example 1. This limit presents an indeterminate form of type 0/0: $$ \lim_{n \rightarrow \infty} \ \frac{\frac{1}{n^2}}{\frac{1}{n}} = \frac{0}{0} $$ By simplifying the expression algebraically, we can resolve the indeterminacy: $$ \lim_{n \rightarrow \infty} \frac{1}{n^2} \cdot \frac{n}{1} = \lim_{n \rightarrow \infty} \frac{1}{n} = 0 $$ Example 2. In some cases, exponential and trigonometric functions can be approximated using Taylor series expansions to evaluate the limit.

  • L’Hôpital’s Rule. When a limit takes on the form 0/0 or ∞/∞ and the functions involved are differentiable, you can apply L’Hôpital’s Rule. This involves taking the derivative of the numerator and denominator - repeating if necessary - until the limit becomes determinate (finite or infinite).

    Example. Consider the following limit, which initially appears as ∞/∞: $$ \lim_{n \rightarrow \infty} \frac{n-1}{n} = \frac{\infty}{\infty} $$ Applying L’Hôpital’s Rule by differentiating numerator and denominator: $$ \lim_{n \rightarrow \infty} \frac{D[n-1]}{D[n]} = \lim_{n \rightarrow \infty} \frac{1}{1} = 1 $$ Therefore, the limit evaluates to 1.

Determinate Forms

Not every occurrence of zero or infinity in a limit leads to an indeterminate form.

For example, the following expressions are not indeterminate:

$$ k + \infty = +\infty $$ A real number k added to infinity
$$ k - \infty = -\infty $$ A real number k minus infinity
$$ \infty+\infty = \infty $$ Infinity plus infinity
$$ k \cdot \infty = \infty $$ A nonzero constant k multiplied by infinity
$$ \infty \cdot \infty = \infty $$ Infinity times infinity
$$ \frac{k}{\infty} = 0 $$ A constant k divided by infinity
$$ \frac{0}{\infty} = 0 $$ Zero divided by infinity
$$ \frac{\infty}{k} = \infty $$ Infinity divided by a nonzero constant k
$$ \frac{k}{0} = \infty $$ A nonzero constant k divided by zero

In these cases, the outcome is algebraically clear and well-defined. They are not considered indeterminate forms.

And so on.

 

 
 

Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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