Right-Hand Limit

A function f(x), defined on an interval (c, d), is said to have a right-hand limit as x approaches c from the right if: $$ \lim_{x \rightarrow c^+} f(x) = l $$ In other words, for any ε > 0, there exists a δ > 0 such that whenever $$ c < x < c + δ, \text{ then } |f(x) - l| < ε. $$

an example illustrating the right-hand limit

For the right-hand limit to exist, this condition must hold over the open interval (c, c + δ), which includes values strictly greater than c.

Note. When evaluating the right-hand limit of a function at a point c, we consider only values approaching c from the right. Values to the left of c - or the value of the function exactly at c - are not relevant for the right-hand limit and may or may not exist independently.

    A Practical Example

    Let’s examine the function f(x) = x2 at the point c = 2.

    The right-hand limit of the function is:

    $$ \lim_{x \rightarrow 2^+} f(x) = 4 $$

    Verification

    Let’s choose an arbitrary value ε = 5, which is greater than zero.

    $$ l + ε = 4 + 5 = 9 $$

    This allows us to select a value δ = 1, also greater than zero, and define the interval:

    $$ (c, c + δ) = (2, 2 + 1) = (2, 3) $$

    For any x within the open interval (2, 3) on the x-axis, the absolute difference between f(x) and the right-hand limit l is less than ε.

    Therefore, the right-hand limit of the function f(x) at x = 2 is indeed 4.

    verification of the right-hand limit for the function

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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