Left-Hand Limit

A function f(x), defined on an interval (a, c), is said to have a left-hand limit as x approaches c from the left if: $$ \lim_{x \rightarrow c^-} f(x) = l $$ In other words, for any ε > 0, there exists a δ > 0 such that whenever $$ c - δ < x < c, \text{ then } |f(x) - l| < ε. $$

graph illustrating the left-hand limit

For the left-hand limit to exist, the definition must hold over the open interval (c - δ, c), which includes values strictly less than c.

Note. When evaluating the left-hand limit of a function at a point c, we only consider values approaching c from the left. We do not take into account values to the right of c (which pertain to the right-hand limit), nor the function’s value exactly at c itself. These may or may not exist independently of the left-hand limit.

    A Practical Example

    Let’s examine the function f(x) = x2 at the point c = 3.

    The left-hand limit of the function is:

    $$ \lim_{x \rightarrow 3^-} f(x) = 9 $$

    Verification

    First, choose an arbitrary value ε = 5, which is greater than zero.

    $$ l - ε = 9 - 5 = 4 $$

    This allows us to find a value δ = 1, also greater than zero, and define the interval:

    $$ (c - δ, c) = (3 - 1, 3) = (2, 3) $$

    For any x within the open interval (2, 3) along the x-axis, the absolute difference between f(x) and the left-hand limit l is less than ε.

    Therefore, the left-hand limit of the function f(x) at the point c is indeed 9.

    verification of the left-hand limit of the function

     

     
     

    Please feel free to point out any errors or typos, or share suggestions to improve these notes. English isn't my first language, so if you notice any mistakes, let me know, and I'll be sure to fix them.

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